Задача 75484 ...

632f635587d19127bff140f0

1/20/2024 9:05:08 AM

Найдите значение выражения: 4sin (–π/3) – 3ctg (–π/3) + 5cos (–π/6)
ответы: 0; 3√ 3/2; √ 3; 11 √3/2.

626fab9a354ab65fb2f43abb

1/20/2024 12:03:45 PM

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4sin (–π/3) – 3ctg (–π/3) + 5cos (–π/6) =
= -4sin(π/3) + 3ctg(π/3) + 5cos(π/6) =
= -4*sqrt(3)/2 + 3*sqrt(3)/3 + 5sqrt(3)/2 =
= sqrt(3)/2 + sqrt(3) = 3sqrt(3)/2

Ответ: 2) 3sqrt(3)/2