2 задание пж
[m]\frac{AC}{sin ∠ABC}=\frac{BC}{sin ∠BAC }[/m] sin30 ° =[m]\frac{1}{2}[/m] [m]\frac{2}{\frac{1}{2}}=\frac{2\sqrt{3}}{sin ∠BAC }[/m] ⇒ [m]2sin ∠BAC =\frac{1}{2}\cdot 2\sqrt{3}[/m] [m]sin∠BAC=\frac{\sqrt{3}}{2}[/m] ∠BAC=60 °