так как при[m] x → 0[/m]
[m]e^{-2x}→ 1[/m]
[m]5^{-x}→ 1[/m]
[m]=lim_{x → 0}\frac{(1-e^{2x})} {(1-(\frac{3}{5})^{-x})}=lim_{x → 0}\frac{(e^{2x}-1)}{ ((\frac{5}{3})^{x}-1)}=lim_{x → 0}\frac{(e^{2x}-1)}{2x}\cdot \frac{2x}{ln\frac{5}{3}x}\cdot \frac{ln\frac{5}{3}x}{((\frac{5}{3})^{x}-1)}=2ln\frac{5}{3}[/m]