[m]\left\{\begin {matrix}x^2-x-12 ≤ 0\\x^2+4x+10 ≥ 0\\x ≠0 \end {matrix}\right.[/m]
x^2-x-12=0
D=1-4*(-12)=49
x^2-x-12=(x+3)(x-4)
x^2+4x+10 =0
D=4^2-4*10 <0
x^2+4x+10 >0 при любом х
[m]\left\{\begin {matrix}(x+3)(x-4) ≤ 0\\x ≠0 \end {matrix}\right.[/m]
[b]x ∈ [-3;0) U (0;4][/b]