[m](\sqrt{2}-\sqrt{6}i)^{8}=(\sqrt{2})^{8}\cdot (1-\sqrt{3}i)^{8}=(\sqrt{2})^{8}\cdot 2^{8}\cdot (cos\frac{π}{3}-isin\frac{π}{3})^{8}=2^{12}\cdot (cos\frac{8π}{3}-isin\frac{8π}{3})=2^{12}\cdot (cos(2π+\frac{2π}{3})-isin(2π+\frac{2π}{3}))=[/m]
[m]=2^{12}\cdot (cos\frac{2π}{3}-isin\frac{2π}{3})=2^{11}(-1-\sqrt{3}i)=2048(-1-\sqrt{3}i)[/m]