log0,1(x^3-25x-5x^2+125)≤log0,01(x-5)^4
ОДЗ:
{x^3–25x–5x^2+125>0 ⇒ (x^3+125)-(5x^2+25x)>0 ⇒ (x+5)*(x-5)^2>0
{(x–5)^4>0 ⇒ x ≠ 5
x>-5; x ≠ 5
log_(0,1)(x^3–25x–5x^2+125)≤log_((0,1)^2)(x–5)^4
log_(0,1)(x^3–25x–5x^2+125)≤log_(0,1)(x–5)^2
Логарифмическая функция с основанием 0,1 убывающая
x^3–25x–5x^2+125 ≥(x–5)^2
(x+5)*(x-5)^2≥(x–5)^2
(х+5)*(x-5)^2- (x–5)^2 ≥ 0
(х-5)^2*(x+5-1) ≥ 0
(x-5)^2*(x+4) ≥ 0
x ≥ -4
c учетом ОДЗ:
О т в е т. [-4;5) U(5;+ ∞ )