[m]\frac{\sqrt{2}}{2}sin α +\frac{\sqrt{2}}{2}cos α =cos\frac{π}{4}sin α +sin\frac{π}{4}cos α=sin(\frac{π}{4}+ α) [/m]
[m]\frac{\sqrt{2}}{2}sin α +\frac{\sqrt{2}}{2}cos α+3=sin(\frac{π}{4}+ α) +3 [/m]
[m]- 1≤ sin(\frac{π}{4}+ α) ≤1 [/m]
[m]- 1+3≤ sin(\frac{π}{4}+ α) +3 ≤1+3 [/m] ⇒ [b]2[/b] [m]≤ sin(\frac{π}{4}+ α) +3 ≤ [/m][b]4[/b]
Наибольшее значение
[m]\frac{2}{2}=1[/m]