2sin^2x + 5cosx = -1
sin^2x=1-cos^2x 2*(1-cos^2x)+5cosx=-1 2cos^2x-5cosx-3=0 D=25-4*2*(-3)=49 cosx=3 или cosx=-1/2 cosx=-1/2 x= ± arccos(-1/2)+2πn, n ∈ [b]Z[/b] x= ± (π-arccos(1/2))+2πn, n ∈ [b]Z[/b] x= ± (2π/3)+2πn, n ∈ [b]Z[/b]