Задача 71120 (sin xdx)/(cos^2 x-9)...

6392f6d1b41a584e46e6a891

30.04.2023 11:29:31

(sin xdx)/(cos^2 x-9)

5f3ea7e3faf909182968ddd9

30.04.2023 15:27:07

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d(cosx)=-sinxdx

⇒ sinxdx=-du

u=cosx

[m]∫\frac{sinxdx}{cos^2x-9}=- ∫\frac{du}{u^2-9}= -\frac{1}{2\cdot 3}ln|\frac{cosx-3}{cosx+3}|+C[/m]