Задача 71051 { x+2 < log2(24/y) { log4(x/y) =...

6182340a3d5d7c0560db11d7

27.04.2023 10:30:39

{ x+2 < log2(24/y)
{ log4(x/y) = (x/2)^(log(x/2) 2 - 1)

5f3ea7e3faf909182968ddd9

27.04.2023 10:46:28

★

[m]\left\{\begin {matrix}2^{x+2}<2^{log_{2}(\frac{24}{y})}\\\frac{24}{y}>0\\log_{2^2}\frac{x}{y}=2-1\\\frac{x}{2}>0\\\frac{x}{2} ≠1 \end {matrix}\right.[/m]


[m]\left\{\begin {matrix}2^{x}\cdot 2^2<\frac{24}{y}\\y>0\\\frac{1}{2}log_{2}\frac{x}{y}=1\\x>0\\x ≠2 \end {matrix}\right.[/m]


[m]\left\{\begin {matrix}2^{x}<\frac{6}{y}\\y>0\\log_{2}\frac{x}{y}=2\\x>0\\x ≠2 \end {matrix}\right.[/m]

[m]\left\{\begin {matrix}2^{x}<\frac{6}{y}\\y>0\\\frac{x}{y}=4\\x>0\\x ≠2 \end {matrix}\right.[/m]

О т в е т.
Системе удовлетворяют точки плоскости от О до А и от А до В

{(x;y) ∈ R^2| x ∈ (0;2)U(2;log_(2)3);y=(1/4)x}