cosx/(1+sinx) + (1+sinx)/cosx = 2/cosx
[m]\frac{cosx}{1+sinx}+\frac{1+sinx}{cosx}= \frac{cos^2x+(1+sinx)^2}{cosx(1+sinx)}= \frac{cos^2x+1+2sinx+sin^2x}{cosx(1+sinx)}=[/m] [m]=\frac{2+2sinx}{cosx(1+sinx)}=\frac{2(1+sinx)}{cosx(1+sinx)}= \frac{2}{cosx}[/m]