Задача 70844 [red]Очень надо [/red] сpочно ...
Условие
Решение
0,3a^(-6)b^(-11)*2a^7b^(12) = 0,3*2*a^(-6+7)*b^(-11+12) =0,6ab
При a = 10; b = 2 получаем:
0,6ab = 0,6*10*2 = 12
3) 3^(-2) = 1/3^2 = 1/9
(-5)^(-2) = 1/(-5)^2 = 1/25
[m](\frac{4}{9})^{-2} = (\frac{9}{4})^2 = \frac{9^2}{4^2} = \frac{81}{16}[/m]
(0,1)^(-4) = (1/10)^(-4) = 10^4 = 10000
[m](2 \frac{1}{3})^{-3} = (\frac{2 \cdot 3+1}{3})^{-3} = (\frac{7}{3})^{-3}=(\frac{3}{7})^3 = \frac{27}{343} [/m]
8^(-1) + 6^(-2) = 1/8 + 1/6^2 = 1/8 + 1/36 = 9/72 + 2/72 = 11/72
456^0 - (0,1)^(-3) = 1 - (1/10)^(-3) = 1 - 10^3 = 1 - 1000 = -999
4) [m]\frac{5^{-3} \cdot 5^{-9}}{5^{-11}} = \frac{5^{-3-9}}{5^{-11}} = \frac{5^{-12}}{5^{-11}} = 5^{-12+11} = 5^{-1} = \frac{1}{5} = 0,2[/m]