= |- 1^3/3 - 1 - (-(-2^3)/3 - (-2))| = |- 1/3 - 1 - 8/3 - 2| =
= |-9/3 - 3| = |-3 - 3| = |-6| = 6
S = 6
[m]S= ∫^{b}_{a} (g(x)-f(x))dx[/m]
f(x)=-x^2-1
g(x)=0
[m]S= ∫^{1}_{-2} (0-(-x^2-1))dx=∫^{1}_{-2} (x^2+1)dx=(\frac{x^3}{3}+x)|^{1}_{-2}=(\frac{1^3}{3}+1)-(\frac{(-2)^3}{3}+(-2))=\frac{1}{3}+1+\frac{8}{3}+2=3+3=6[/m]