lim ∨ x → 2 x ∧ 2 -4 ÷ x ∧ 2-3x+2 хелп!
[m]lim_{x \to 2} \frac{x^2-4}{x^2-3x+2}=lim_{x \to 2} \frac{(x-2)(x+2)}{(x-2)(x-1)}= lim_{x \to 2} \frac{x+2}{x-1} = \frac{2+2}{2-1} = 4[/m]
