Получим:
[m]\frac{(1-\frac{1}{5})(1+\frac{1}{5})(1+\frac{1}{5^2})(1+\frac{1}{5^4})\cdot ...\cdot(1+\frac{1}{5^{16}}) }{(1-\frac{1}{5})}=[/m]
Применяем формулу : [r][m] (a-b)(a+b)=a^2-b^2)[/m][/r]
[m]=\frac{(1-\frac{1}{5^2})(1+\frac{1}{5^2})(1+\frac{1}{5^4})\cdot ...\cdot(1+\frac{1}{5^{16}}) }{\frac{4}{5}}=[/m]
[m]=\frac{(1-\frac{1}{5^4})(1+\frac{1}{5^4})\cdot ...\cdot(1+\frac{1}{5^{16}}) }{\frac{4}{5}}=...[/m]
[m]=\frac{1-\frac{1}{5^{32}} }{\frac{4}{5}}=\frac{5(1-\frac{1}{5^{32}})}{4}=\frac{5-\frac{1}{5^{31}}}{4}[/m]