[m]S= ∫ ∫ dxdy= ∫_{-2}^{10} dx∫ _{-8x}^{20-x^2}dy= ∫_{-2}^{10} (y)| _{-8x}^{20-x^2}dx=∫_{-2}^{10}(20-x^2-(-8x))dx=∫_{-2}^{10}(20-x^2+8x)dx=(20x-\frac{x^3}{3}+8\frac{x^2}{2})|_{-2}^{10}=[/m]
[m]=20\cdot 10-\frac{10^3}{3}+4\cdot 10^2)-(20\cdot (-2)-\frac{(-2)^3}{3}+4\cdot (-2)^2=[/m]
20-x^2=-8x
x^2-8x-20=0
x_(1)=-2;x_(2)=10
D:
-2 ≤ x ≤ 10
-8x ≤ y ≤ 20-x^2