если 2d-e=505 и 3e-k=333, то 4d+7e-3k равно?
[b] 2d–e[/b]=505 [blue] [b]3e–k[/b][/blue]=333 4d+7e–3k=2d+2d+3e-k+3e-k+e-k=2d-e+2d-e+3e-k+3e-k+3e-k=2*[b](2d-e[/b])+3*[blue][b](3e-k)[/b][/blue]=2*505+3*333