Решите неравенство 7х^(2)+19х-6 ≤ 0
7x^(2)+19x-6 ≤ 0, 7x^(2)+19x-6=0, D=361+168=529=23^(2), x=(-19 ± 23)/14, x_(1)=-3, x_(2)=2/7, 7(x+3)(x-(2/7)) ≤ 0, (x+3)(x-(2/7)) ≤ 0, -3 ≤ x ≤ (2/7), x ∈ [-3; (2/7)]. Ответ: [-3; (2/7)].