cos 2х – cos х = cos 3х
cos2x=cos3x+cosx cos2x=2cos2x*cosx cos2x-2cos2x*cosx=0 cos2x*(1-2cosx)=0 cos2x=0 или 1-2cosx=0 2x=(π/2)+πn, n ∈ Z [b]x=(π/4)+(π/2)*n, n ∈ Z[/b] или 1-2cosx=0 сosx=1/2 x= ± arccos(1/2)+2πk, k ∈ Z [b]x= ± (π/3)+2πk, k ∈ Z[/b]