Виконайте дії:x²/x²-9 - x/x-3
(x²)/(x²–9) –( x)/(x–3)=(x²)/((x-3)(х+3)) –( x)/(x–3)=(x²)/((x-3)(х+3)) –( x)(x+3)/(x–3)(x+3)= =(x²)/((x-3)(x²+3x)) –( x+3x)/(x–3)(x+3)=(x²-x²-3x)/((x-3)(х+3)) =[b](-3x)/(x^2-9)[/b]