б) [m](a-b^{1/4})(a+b^{1/4}) + \sqrt{b} = a^2 - b^{1/2} + b^{1/2} = a^2[/m]
в) [m]\sqrt[3]{\frac{n^2}{9m}} : \sqrt[3]{\frac{3m^2}{n}} = \sqrt[3]{\frac{n^2}{9m}} * \sqrt[3]{\frac{n}{3m^2}} =[/m]
[m] = \sqrt[3]{\frac{n^2*n}{9m*3m^2}} = \sqrt[3]{\frac{n^3}{27m^3}} = \frac{n}{3m}[/m]