Сократите дробь 24^n/2^3n-2 * 3^n-1
[m]\frac{24^{n}}{2^{3n–2}\cdot 3^{n–1}}=\frac{(2^3\cdot 3)^{n}}{2^{3n–2}\cdot 3^{n–1}}=\frac{2^{3n}\cdot 3^{n}}{2^{3n–2}\cdot 3^{n–1}}=2^{3n-(3n-2)}\cdot 3^{n-(n-1)}=2^2\cdot 3=12[/m]
