б) ∫ [m]\sqrt[6]{9-4x} dx = ∫ (9-4x)^{1/6} dx = -1/4*\frac{(9-4x)^{7/6}}{7/6} + C = [/m]
[m] = -1/4*6/7*(9-4x)^{7/6} + C = -3/14(9-4x)^{7/6} + C [/m]
в) ∫_1^2 [m](5^{2x}) dx = 1/2*\frac{5^{2x}}{ln 5} |_1^2 = \frac{1}{2ln 5}(5^4 - 5^2) = \frac{1}{2ln 5}*(625-25) = \frac{600}{2ln 5} = \frac{300}{ln 5}[/m]