D:
-2 ≤ y ≤ 4
-2y ≤ x ≤ 8-y^2
S= ∫ _(-2)^(4) ([blue] ∫ _(-2y)^(8-y^2)dx[/blue])dy=
=∫ _(-2)^(4) ([blue]x[/blue])| _(-2y)^(8-y^2) dy=
=∫ _(-2)^(4) [b]([/b][blue](8-y^2)- (-2y)[/blue] [b])[/b] dy=
=∫ _(-2)^(4)(8-y^2+2y)dy=
=(8y - (y^3/3)+y^2)|_(-2)^(4)=
=(8*4 - (4^3/3)+4^2)-(8*(-2) - ((-2)^3/3)+(-2)^2)= считайте....