Решите задачи 2
1. AO=H*ctg α AO=R R=asqrt(3)/3 a=AB=BC=AC=sqrt(3)*AO=sqrt(3)*H*ctg α V=(1/3)*(1/2)*a^2(sqrt(3)/4)*H=(1/6)*3H^2ctg^2 α *H=[b](H^3ctg^2 α )/2[/b] 2. a=h=1 О т в е т.[red] [b] 6+3sqrt(3)[/b][/red]