x^(1/2)+y^(1/2)=5
x^(1/4)-y^(1/4)=1
{x^(1/4)–y^(1/4)=1
Замена:
x^(1/4)=u
x^(1/2)=(x^(1/4))^2=u^2
y^(1/4)=v
y^(1/2)=(y^(1/4))^2=v^2
{u^2+v^2=5
{u-v=1 ⇒ u=v+1
(v+1)^2+v^2=5
v^2+2v+1+v^2=5
2v^2+2v-4=0
v^2+v-2=0
v_(1)=-2; v_(2)=1
y^(1/4)=v
y^(1/4)=-2 нет корней
y^(1/4)=1
y=1
u=1+1=2
x^(1/4)=u
x^(1/4)=2
x=16
О т в е т.[b]х=16; у=1[/b]