Решить уравнение
[m](\sqrt{2}tg2x-1)(\sqrt{2}tg2x+1) >0[/m] ⇒ [m]-\frac{1}{\sqrt{2}}< tg2x < \frac{1}{\sqrt{2}}[/m] [m]arctg(-\frac{1}{\sqrt{2}})+πn< 2x < arctg(\frac{1}{\sqrt{2}})+πn, n ∈ [/m][b]Z[/b] [m]-\frac{π}{4}+πn< 2x < \frac{π}{4}+πn, n ∈ [/m][b]Z[/b] [m]-\frac{π}{8}+\frac{π}{2}n< 2x < \frac{π}{8}+\frac{π}{2}n, n ∈ [/m][b]Z[/b]