[m](\sqrt{6-\sqrt{11}}+\sqrt{6-\sqrt{11}})^2=(\sqrt{6-\sqrt{11}})^2+2\cdot \sqrt{6-\sqrt{11}}\cdot \sqrt{6-\sqrt{11}}+(\sqrt{6-\sqrt{11}})^2=[/m]
[m]=6-\sqrt{11}+2\sqrt{6^2-(\sqrt{11})^2}+6+\sqrt{11}=12+2\sqrt{36-11}=12+2\sqrt{25}=12+10=22[/m]
[m]\frac{1}{4+2\sqrt{3}}+\frac{1}{4-2\sqrt{3}}=\frac{(4-2\sqrt{3})+(4+2\sqrt{3})}{(4+2\sqrt{3})(4-2\sqrt{3})}=\frac{4-2\sqrt{3}+4+2\sqrt{3}}{4^2-(2\sqrt{3})^2}=\frac{8}{16-12}=\frac{8}{4}=2[/m]
[m]\sqrt[3]{\sqrt{52}-5}\cdot \sqrt[3]{\sqrt{52}+5}=\sqrt[3]{(\sqrt{52}-5)(\sqrt{52}+5)}=\sqrt[3]{(\sqrt{52})^2-5^2}=\sqrt[3]{52-25}=\sqrt[3]{27}=3[/m]