cos γ =cos45 ° =sqrt(2)/2
cos^2 α +cos^2 β +cos^2 γ =1
⇒
cos^2 β =1-cos^2 α -cos^2γ =1-(1/2)-(1/2)=0
cos β =0
β =90 °
vector{r}=(a_(x);a_(y);a_(z))
|vector{r}|=6
cos α=a_(x)/|vector{r}| ⇒ a_(x)=|vector{r}|*cos α =6*(-sqrt(2)/2)=-3sqrt(2)
cos β =a_(y)/|vector{r}| ⇒ a_(y)=|vector{r}|*cos β =6*0=0
cos γ =a_(z)/|vector{r}| ⇒ a_(z)=|vector{r}|*cos γ =6*(sqrt(2)/2)=3sqrt(2)
О т в е т. vector{r}=(-3sqrt(2); 0; 3sqrt(2))