Задача 61245 ...

617cdf968c4c5a5ade8c28d8

30.10.2021 09:11:23

sinx - √2sin3x=-sin5x

61703bbe8c4c5a5ade8bf113

30.10.2021 12:29:01

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Sinx + Sin5x - √2Sin3x= 0
2Sin3x Cos2x - √2Sin3x = 0
Sin3x(2Cos2x - √2) = 0
Sin3x = 0
3x = πn , n ∈Z
x = πn/3, n ∈Z

Или
2Cos2x - √2 = 0
Cos2x = √2/2
2x = +-π/4 + 2πk , k ∈Z
x = +-π/8 + πk , k ∈Z