a) HX
b) HY
c) DF
d) найдите синус угла DXH.
HX^2=YT^2+EX^2=8^2+5^2=64+25=89
НX=sqrt(85)
b)
HY^2=HG^2+YG^2=10^2+4^2=100+16=116
HY=sqrt(116)
c)
DF^2=DH^2+[b]HF^2[/b]=DH^2+([b]HE^2+EF^2[/b])=6^2+8^2+10^2=25+64+100=189
DF=sqrt(189)
d)
sin ∠ DXH=DH/DX
DX^2=DH^2+HX^2=6^2+89=36+89=125
DX=sqrt(125)=5sqrt(3)
sin ∠ DXH=DH/DX=6/5sqrt(3)