(log 2 (5)+ log 5 (2)+2)(log 2 (5)- lg 5 ) log 5 (2) - log 2 (5)
(1/log(2)5+log(2)5+2)*(1/log(2)5 -1/(1+log(2)5)*log(2)5-1/log(2)5=
=(1+log(2)5+2log(2)5)*(1+log(2)5-log(2)5)/[log(2)5*(1+log(2)5]*log(2)5-
1/log(2)5=(1+log(2)5)/log(2)5*1/(1+log(2)5)-1/log(2)5=
=(1+log(2)5)/log(2)5-1/log(2)5=(1+log(2)5-1)/log(2)5=log(2)5/log(2)5=1