[m] ∫_{0} ^{π}(sin\frac{x}{2}+cos\frac{x}{4})dx = ∫_{0} ^{π}sin\frac{x}{2}dx+∫_{0} ^{π}cos\frac{x}{4}dx=\frac{1}{\frac{1}{2}}(-cos\frac{x}{2})|_{0} ^{π}+\frac{1}{\frac{1}{4}}(sin\frac{x}{4})||_{0}^{π} = -2cos\frac{π}{2}+2cos0+4sin\frac{π}{4}-4sin0-2\cdot0+2cdot1+4\cdot \frac{\sqrt{2}}{2}-4\cdot 0=[/m]