Задача 60106 Хелп пж!!!!!...

60b8cbbea1c50e1d3043a673

03.06.2021 15:33:15

Хелп пж!!!!!

5f3ea7e3faf909182968ddd9

03.06.2021 15:51:40

★

[m]\frac{ ∂z }{ ∂x }=(\frac{sin(x-y)}{x})`_{x}=\frac{(sin(x-y))`\cdot x-(sin(x-y))\cdot x`}{x^2}=\frac{cos(x-y)\cdot (x-y))`_{x}\cdot x-(sin(x-y))\cdot1}{x^2}=\frac{cos(x-y)\cdot x-(sin(x-y))}{x^2}[/m]

[m]\frac{ ∂z }{ ∂y }=(\frac{sin(x-y)}{x})`_{y}=\frac{1}{x}\cdot (sin(x-y))`_{y}=\frac{1}{x}\cdot cos(x-y)\cdot (x-y)`_{y}=\frac{1}{x}\cdot cos(x-y)\cdot (-1)=-\frac{cos(x-y)}{x}[/m]

[m]\frac{ ∂^2z }{ ∂x^2 }=(\frac{cos(x-y)\cdot x-(sin(x-y))}{x^2})`_{x}=...[/m]

[m]\frac{ ∂z }{ ∂y }=(-\frac{cos(x-y)}{x})`_{y}=...[/m]