y`=p(y(x))
y``=p`(y)*y`(x)=p`(y)*p
y*p`*p=p-p^2
p`=dp/dy
dp/(1-p)=dy/y
Интегрируем:
∫ dp/(1-p)= ∫ dy/y
-ln|1-p|+lnC=lny
lny+ln(1-p)=lnC
y*(1-p)=C
p=y`
y*(1-y`)=C_(1)
y-y*y`=C_(1)
y`=dy/dx
y-y*dy/dx=C_(1)
y*dx-y*dy=C_(1)*dx
ydy+(C_(1)-y)dx=0
ydy/(y-C_(1))=dx
Интегрируем:
∫ ydy/(y-C_(1))= ∫ dx
∫dy+C_(1) ∫ dy/(y-C_(1))= ∫ dx
[b]y+C_(1)ln|y-C_(1)|=x+C_(2)[/b]