Задача 59681 (x^2-4x+5)^2 = (x^2-2x-1)^2...

607457bb8a393324c629e3ae

11.05.2021 12:53:01

(x^2-4x+5)^2 = (x^2-2x-1)^2

5f3ea7e3faf909182968ddd9

11.05.2021 13:10:11

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(x^2–4x+5)^2 = (x^2–2x–1)^2


(x^2–4x+5)^2 - (x^2–2x–1)^2=0

Применяем формулу

[m]a^2-b^2=(a-b)\cdot (a+b)[/m]

[b]([/b][blue](x^2–4x+5) - (x^2–2x–1)[/blue][b])*([/b][blue](x^2–4x+5) + (x^2–2x–1)[/blue][b])[/b]=0