[m]S= ∫ ^{0}_{-2}(x+2)^2dx=∫ ^{0}_{-2}(x+2)^2d(x+2)=(\frac{(x+2)^3}{3})|^{0}_{-2}=[/m]
[m]=(\frac{(0+2)^3}{3})-(\frac{(-2+2)^3}{3})=\frac{8}{3}[/m]
2)
[m]S= ∫ ^{2}_{0}(2x-x^2)dx=(x^2-\frac{x^3}{3})|^{2}_{0}=(2^2-\frac{2^3}{3})-(0^2-\frac{0^3}{3})=\frac{4}{3}[/m]
3)
[m]S= ∫ ^{2}_{0}(x^3+1-0)dx=(\frac{x^4}{4}+x)| ^{2}_{0}=(\frac{2^4}{4}+2)-(\frac{0^4}{4}+0)=4+2=6[/m]
4)
[m]S= ∫ ^{\frac{π}{2}}_{0}(1+2sinx)dx=(x+2\cdot (-cosx))|{\frac{π}{2}}_{0}=\frac{π}{2}-2cos\frac{π}{2}-(0-2cos0)=\frac{π}{2}+2[/m]
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