4 кто можеть решать?
In the theory of differential equations, it is solved as follows: e^(x)dx=-e^(y)(1-e^(x))dy -e^(x)/(1-e^(x))dx=e^(y)dy ∫( -e^(x))/(1-e^(x))dx= ∫ e^(y)dy ∫ d(1-e^(x))/(1-e^(x))= ∫ e^(y)dy ln|1-e^(x)|=e^(y)+C y(1)=1 ln|1-e^(1)|=e^(1)+C [b]C=ln|1-e|-e[/b]