y=2x+(1/x) ⇒ f(x)=2x+(1/x)
f`(x)=2-(1/x^2)
f(x_(o))=f(1)=2*1+(1/1)=3
f`(x_(o))=f`(1)=2-(1/1^2)=1
y-3=1*(x-1)
[b]y=x+2[/b]
4)
y=x+sqrt(x) ⇒ f(x)=x+sqrt(x)
f`(x)=(x+sqrt(x))`=1+(1/(2sqrt(x)))
f(x_(o))=f(1)=1+sqrt(1)=2
f`(x_(o)))=f`(1)=1+(1/(2sqrt(1)))=3/2
y-2=(3/2)*(x-1)
[b]y=(3/2)x+(1/2)[/b]