Задача 57803 ...

5f54df62356816184059ff63

09.02.2021 19:24:28

y=logx(3^x–2)+cos√(3–x)

5f3ea7e3faf909182968ddd9

09.02.2021 20:15:31

★

[m]\left\{\begin {matrix}x>0\\x ≠1\\3^{x}-2 >0\\3-x>0 \end {matrix}\right.[/m] ⇒ [m]\left\{\begin {matrix}x>0\\x ≠1\\3^{x} >3^{log_{3}2}\\x<3 \end {matrix}\right.[/m]⇒ [m]\left\{\begin {matrix}x>0\\x ≠1\\x >log_{3}2\\x<3 \end {matrix}\right.[/m]

[m]log_{3}2 < log_{3}3 =1[/m]

[m]log_{3}2 > log_{3}1 =0[/m]


О т в е т. [m](log_{3}2;1) \cup(1;3)[/m]