[m]cos(\frac{π}{3}+ α )=sin(\frac{π}{2}-(\frac{π}{3}+ α ))=sin(\frac{π}{2}-\frac{π}{3}- α )=sin(\frac{π}{6}- α )[/m]
[m]\frac{sin(\frac{π}{6}+ α )-cos(\frac{π}{3}+ α )}{sin(\frac{π}{6}+ α )+cos(\frac{π}{3}+ α )}=\frac{sin(\frac{π}{6}+ α )-sin(\frac{π}{6}- α )}{sin(\frac{π}{6}+ α )+sin(\frac{π}{6}- α )}=[/m]
По формулам:
[r][m] sin α ± sin β =2sin\frac{ α ± β }{2}\cdot cos\frac{ α \mp β }{2}[/m][/r]