По формуле:
[r] sin α *cos β =(1/2) sin ( α + β )+ (1/2) sin ( α - β )[/r]
sin5cos7=(1/2) sin 12+(1/2)sin(-2)=(1/2)sin12-(1/2)sin2
sin10cos2=(1/2)sin12+(1/2)sin8
sin5cos3=(1/2)sin8+(1/2)sin2
(1/2)sin12-(1/2)sin2-(1/2)sin12-(1/2)sin8=-(1/2)sin8-(1/2)sin2 - верно.
Значит и данное равенство верно