Задача 56871 3*4^x+1/3*9^(x+2)=6*4^(x+1)-1/2*9^(x+1)=0...

5f54df62356816184059ff63

12.01.2021 11:47:27

3*4^x+1/3*9^(x+2)=6*4^(x+1)-1/2*9^(x+1)=0

5f3ea7e3faf909182968ddd9

12.01.2021 14:40:34

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(1/3)·9^(x+2)+(1/2)*9^(x+1)=6·4^(x+1)-3·4^x

(1/3)·9^(x)*9^(2)+(1/2)*9^(x)*9^(1)=6· 4^(x)*4^(1)-3·4^(x)

9^(x)*(27+4,5)=4^(x)*(24-3)

[b](9/4)^(x)=21/31,5[/b]

[b](3/2)^(2x)=2/3[/b]

2x=-1

[b]x=-1/2[/b]