f`(x)=((x^2/4)-x+5)`=(2x/4)-1=(x/2)-1
[red]в точке x_(o)=4 [/red]
f (4)=(4^2/4)-4+5=5
f`(4)=(4/2)-1=1
y=5 +1*(x-4)
[b]y=x-1[/b]
v(t)=s`(t)=(-3cos((t/4)+(π/12))+10)`=-3*(-sin(((t/4)+(π/12))*((t/4)+(π/12))`+(10)`=3sin((t/4)+(π/12))*(1/4)=(3/4)sin((t/4)+(π/12))
v(π/3)=(3/4)sin((π/3*4)+(π/12))=(3/4)sin(π/6)=(3/4)*(1/2)=[b](3/8)[/b]