=∫ ^(π/2)_(π/4)dy (∫ ^(3)_(2)12ysin2xydx)=так как d(2xy)=2ydx =∫ ^(π/2)_(π/4)dy (∫ ^(3)_(2)6sin2xy(d[b](2xy[/b]))= =∫ ^(π/2)_(π/4)(6*(-cos2xy)|^(3)_(2))dy= =6∫ ^(π/2)_(π/4)(cos4y-cos6y)dy=((6/4)sin4y-sin6y)|^(π/2)_(π/4)=1,5(sin(2π)-sinπ)-(sin3π-sin(3π/2))=0-1=-1