1)f(x)=2x3–3x2+5 и h(x)=3x2–x–6 при x=2;3;–1.
2)f(x)=5x4–3x2+1 и h(x)=x2–3x–1 при x=2;3;–1.
f(x) + h(x) = 2x³ - 3x² + 5 + 3x² - x - 6 = 2x³ - x - 1
x=2:
2•2³ - 2 - 1 = 16 - 2 - 1 = 13
x=3:
2•3³ - 3 - 1 = 54 - 3 - 1 = 50
x=-1:
2•(-1)³ - (-1) - 1 = -2 + 1 - 1 = -2
Ответ: 13; 50;-2