Задача 55363 ...

5f3ea7e3faf909182968ddd9

07.11.2020 15:47:49

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[m]V_{Ox}=π ∫ ^{4}_{0}(x^2-4x)^2dx=π ∫ ^{4}_{0}(x^4-8x^3+16x^2)dx=π(\frac{x^5}{5}-8\frac{x^4}{4}+16\frac{x^3}{3})|^{4}_{0}=[/m]

[m]=π(\frac{4^5}{5}-8\frac{4^4}{4}+16\frac{4^3}{3})=...[/m]