х − у = 1,
х^2 − 2у^2 = 1.
[m]\left\{\begin{matrix}
y=x-1\\ x^2-2\cdot (x-1)^2=1\end{matrix}\right.[/m] ⇒ [m]\left\{\begin{matrix}
y=x-1\\ x^2-2\cdot (x^2-2x+1)=1\end{matrix}\right.[/m]⇒ [m]\left\{\begin{matrix}
y=x-1\\ x^2-2\cdot x^2+4x-2-1=0\end{matrix}\right.[/m]
[m]\left\{\begin{matrix}
y=x-1\\ -x^2+4x-3=0\end{matrix}\right.[/m]
[m]\left\{\begin{matrix}
y=x-1\\ x^2-4x+3=0\end{matrix}\right.[/m]
D=16-12=4
[m]\left\{\begin{matrix}
y=1-1\\ x=1\end{matrix}\right.[/m] или [m]\left\{\begin{matrix}
y=3-1\\ x=3\end{matrix}\right.[/m]
[m]\left\{\begin{matrix}
y=0\\ x=1\end{matrix}\right.[/m] или [m]\left\{\begin{matrix}
y=2\\ x=3\end{matrix}\right.[/m]
О т в е т. (1;0);(3;2)