[m] a^{\frac{1}{3}}-25=(a^{\frac{1}{6}})^2-5^2=(a^{\frac{1}{6}}-5)\cdot (a^{\frac{1}{6}}+5)[/m]
[m] \frac{a^{\frac{1}{3}}-25}{a^{\frac{1}{6}}+5}= \frac{(a^{\frac{1}{6}}-5)\cdot (a^{\frac{1}{6}}+5)}{a^{\frac{1}{6}}+5}=a^{\frac{1}{6}}-5[/m]
О т в е т. [m]a^{\frac{1}{6}}-5[/m]