=∫ ^(3)_(1)( [blue](1/2)*(x+2y)^(-1)/(-1)[/blue])|^)5)_(2)dx=
=∫ ^(3)_(1)( [blue](1/2)(x+2*5)^(-1)-(1/2)(x+2*2)^(-1)[/blue])dx=
=(1/2)*∫ ^(3)_(1)( [blue]dx/(x+10) [/blue])-(1/2)*∫ ^(3)_(1)( [blue]dx/(x+4) [/blue])=
=(1/2)(ln|x+10|)|^(3)_(1)-(1/2)*(ln|x+4|)^(3)_(1)=
=(1/2)ln13-(1/2)ln11-(1/2)ln7+(1/2)ln5=
=(1/2)ln13*5-(1/2)ln11*7=[b](1/2)ln (65/77)[/b]